Re: Re: Golden Section and


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Posted by Numerologist... on February 29, 2004 at 18:47:09:

In Reply to: Re: Golden Section and posted by Rick Denney on February 28, 2004 at 23:44:25:

Well, frequencies of adjacent tones in the western equally-tempered chromatic scale are related to one another by the twelfth root of 2, which is closely approximated by the quantity 1 1/18. In other words, the frequency of the next higher note is related to its predecessor by being approximately 1/18 again as great.

There are 12 semitones in a chromatic scale and 12/18 can be reduced to 2/3. Amazingly, 2 and 3 are both Fibonacci numbers!

Wow.

IOW, if one casts one's net looking for relationships that aren't there, one can usually find something.

The letters in "York" if taken as numeric quantites, with "A" being 1, "B" being 2 and so on are 25 15 18 11. Added together, they make 69, which is the sum of the three Fibonacci numbers 55+13+1!

Doing the same with the name "Holton" gives a total of 8+15+12+20+15+14 = 84, which is the sum of--again, three Fibonacci numbers 8+21+55.

Not only that, but adding "York" and "Holton" gives a total of 153, and 1, 5 and 3 are all Fibonacci numbers--and again, miraculously the sum of just three Fibonacci numbers, 144+8+1!

Multiply 84 by 69 and you'll get 5796, the sum of the 4 Fibonacci numbers 4181+1597+13+5, which is the same number of letters in the name "YORK"--and "TUBA", whose sum is 20+21+2+1 = 44, which is the sum of exactly three Fibonacci numbers, 33+8+2!

Mere coincidence--or not?

C "Just funnin' with ya"(G)




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