Re: Re: Re: why compensating, really?


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Posted by Matt G on April 22, 2001 at 11:51:36:

In Reply to: Re: Re: why compensating, really? posted by Frederick J. Young on April 21, 2001 at 22:11:41:

Common bore of a Bb flugelhorn equals: .413
.413/2=.2065; .2065 * .2065 * pi=.133964579 square inches of bore.

Common BBb tuba bore equals: .750
.750/2=.375; .375 * .375 * pi=.441786466 square inches of bore. (roughly 3.3 times the fluegel horn bore)

If we multiply .413 * 4 = 1.652
1.652/2=.826; .826 * .826 * pi=2.143433269 square inches of bore. (roughly 16 times the flugelhorn bore)

In your perfect world we can assume that four times the flugel horn bore in SQUARE INCHES (because were dealing with volume which requires three dimensions where as you were using only two LxW for a overall generalization not factoring pi as the third variable in volume) to be: .535858316. We take this number and:
.535858316/pi =.170568999; take it's square root = .412999999 * 2= .825999999. that is four times the flugel horn bore in surface area then we use the length to determine the volume. Granted there aren't a lot of tubas with this size bore but they do exist (5/4 rudy's & cerveny's). Volume in open pipe resonance has a great deal to do with pitch and pitch control as well as overton placement. To take on dimension and then quadruple it beacause dimension has is absurd. We cannot vary pi, so we must take it into account when we do are permutations on the "perfect" bore for a tuba.

Matt G


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